A body is projected vertically upwards with a velocity of 10 m/s. The maximum height reached by the body is:

The correct option is A $5m$
Initial velocity of the body, $u=10$ $m/s$ (Taking upward motion to be positive)

Acceleration of the body, $a=g=-10$ $m/s^2$

At maximum height, the final velocity of the body is zero, i.e. $v=0$

Using: $v^2-u^2=2gS$

$\therefore$ $0-{10}^2=2(-10)H_{max}$

$⟹$ $H_{max}=\frac{{10}^2}{2\times 10}=5m$