A body is thrown horizontally from the top of a tower of height $5 m$ . It touches the ground at a distance of $10 m$ from the foot of the tower. The initial velocity of the body is $(g = 10 m s^{- 2})$

2.5 {m s}^{- 1}

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5 {m s}^{- 1}

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10 {m s}^{- 1}

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20 {m s}^{- 1}

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Solution

The correct option is A $2.5 {m s}^{- 1}$
Height of the tower $H = 5 m$
Time of flight $T = \sqrt{\frac{2 H}{g}} = \sqrt{\frac{2 \times 5}{10}} = 1 s$
Range of projectile is $R = 10 m$
Initial velocity of projectile $u = \frac{R}{T} = \frac{10}{1} = 10 m / s$

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