A body of mass $10 k g$ is moving with a velocity $20 m s^{- 1}$ . If the mass of the body is doubled and its velocity is halved, find the ratio of the initial kinetic energy to the final kinetic energy.

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Solution

Given , Mass of object, $m = 10 k g$
Velocity of object, $v = 20 m s^{- 1}$
Initial Kinetic energy, $K_{1} = \frac{1}{2} \times 10 \times 20^{2} = 2000 J$

Now, Final mass, $m_{2} = 20 k g$
Final Velocity, $v_{2} = 10 m / s$

Final Kinetic energy, $K_{2} = \frac{1}{2} \times 20 \times 10^{2} = 1000 J$

Required Ratio = $\frac{K_{1}}{K_{2}} = \frac{2000}{1000} = 2 : 1$

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A body of mass 10kg is moving with a velocity 20ms−1. If the mass of the body is doubled and its velocity is halved, find the ratio of the initial kinetic energy to the final kinetic energy.

Given , Mass of object, m=10 kgVelocity of object, v=20ms−1Initial Kinetic energy, K1=12×10×202=2000 JNow, Final mass, m2=20 kgFinal Velocity, v2=10m/sFinal Kinetic energy, K2=12×20×102=1000 JRequired Ratio = K1K2=20001000=2:1

A body of mass $10 k g$ is moving with a velocity $20 m s^{- 1}$ . If the mass of the body is doubled and its velocity is halved, find the ratio of the initial kinetic energy to the final kinetic energy.