A body of mass $10 m g$ is moving with a velocity of $100 {m s}^{- 1}$ . The wavelength of the de Broglie wave associated with it would be

6.63 \times 10^{- 7} m

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6.63 \times 10^{- 31} m

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6.63 \times 10^{- 4} m

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6.63 \times 10^{- 35} m

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Solution

The correct option is A $6.63 \times 10^{- 31} m$
de Broglie wavelength $λ = \frac{h}{m v}$
$λ = \frac{6.626 \times 10^{- 34}}{10 \times 10^{- 6} \times 100}$
$[h = 6.626 \times 10^{- 3} J / s e c; m = 10 m g = 10 \times 10^{- 6} k g; v = 100 m / s e c]$
or $λ = 6.626 \times 10^{- 31} m$

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(plancks's constant, h = 6.63 \times 10^{- 34} J s)

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