a body of mass 2 kg is projected upwards with a velocity 4 metre per second. The kinetic energy of the body just before striking the ground is what?
answer:16J
please explain the answer in detail.

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Solution

KE just before striking the ground will be maximum. But once it hits the ground it becomes 0 ie minimum. So, maximum KE

The formula for KE is 1/2 m v^2
So mass is 2 kg

Velocity is 4 m/s

Max. K.E. = 1/2 × 2 × 4^2 =16 J

Hopping it was easy to understand.

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a body of mass 2 kg is projected upwards with a velocity 4 metre per second. The kinetic energy of the body just before striking the ground is what? answer:16J please explain the answer in detail.

KE just before striking the ground will be maximum. But once it hits the ground it becomes 0 ie minimum. So, maximum KE The formula for KE is 1/2 m v^2 So mass is 2 kg Velocity is 4 m/s Max. K.E. = 1/2 × 2 × 4^2 =16 J Hopping it was easy to understand.

a body of mass 2 kg is projected upwards with a velocity 4 metre per second. The kinetic energy of the body just before striking the ground is what?
answer:16J
please explain the answer in detail.

KE just before striking the ground will be maximum. But once it hits the ground it becomes 0 ie minimum. So, maximum KE

The formula for KE is 1/2 m v^2
So mass is 2 kg

Velocity is 4 m/s

Max. K.E. = 1/2 × 2 × 4^2 =16 J

Hopping it was easy to understand.