A body of mass $50 k g$ has a volume of $0.049 m^{3}$ . The buoyant force on it when it is completely immersed inside the water would be

50 k g f

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

49 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

49 k g f

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $49 k g f$
buoyant force = density of water $\times$ volume inside water
= 1000 $k g / m^{3} \times 0.049 m^{3}$
Buoyant fore = 49 kgf.

Suggest Corrections

Similar questions

0.049 m^{3}

A body has a weight 50 N in air. After immersing completely in liquid it's weight is 20 N. Then the buoyant force on the body will be

A body of volume 50 centimetre cube is completely immersed in water. Find the force of buoyancy on it.

m^{3}

Join BYJU'S Learning Program