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Relative Density

A body of vol...

Question

A body of volume 100 $c m^{3}$ weighs 1 kgf in air.

Find : (i) its weight in water and (ii) its relative density.

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Solution

(i) 1kg f = 1000 g f

100 cc of water weighs 100 g f

Upthrust = 100g f

Hence weight in water = 1000 - 100 = 900 g f
= 0.9 kgf

(ii) Relative density (σ) = $\frac{D e n s i t y o f b o d y}{D e n s i t y o f w a t e r}$
= $\frac{\frac{M a s s o f b o d y}{V o l u m e o f b o d y}}{D e n s i t y o f w a t e r}$
= $\frac{\frac{1000 g}{100 c m^{3}}}{\frac{1 g}{c m^{3}}}$
= 10

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