A body projected horizontally with 98 $m{s}^{-1}$ from the top of a tower reaches the ground in 10s. Then it strikes the ground at angle:

Q. A ball is projected at an angle of ${30}^0$ above with the horizontal from the top of a tower and strikes the ground in $5$ sec at an angle of ${45}^0$ with the horizontal. Find the height of the tower and the speed with which it was projected.

Q. A body is projected horizontally from the top of a tower with initial velocity 18 $m{s}^{-1}$. It hits the ground at angle ${45}^{\circ }$. What is the vertical component of velocity when it strikes the ground

Q. A body is projected horizontally from the top of a tower with initial velocity $18m{s}^{-1}$. It hits the ground at angle ${45}^{\circ }$. What is the vertical component of velocity when strikes the ground?

Q. A body is projected horizontally from the top of a tower with an initial velocity of $18{\text{ms}}^{-1}$. It hits the ground at an angle of ${45}^{\circ }$ with horizontal. What is the vertical component of velocity when the body strikes the ground?

Q. Single Correct Answer Type
A body of mass $m$ is projected horizontally with a velocity $v$ from the top of a tower of height $h$ and it reaches ground at a distance $x$ from the top of a tower. If a second body of mass $2m$ is projected horizontally from the top of a tower of height $2h$, it reaches the ground at a distance $2x$ from the tower. The horizontal velocity of second body is