A boy playing on the roof of a $10m$ high building throws a ball with a speed of $10m/s$ at an angle of ${30}^o$ with horizontal. How far from the throwing point will the ball be at the height of $10m$ from the ground ? $(g=10m/s^2)$

Q.

A boy playing on the roof of a 10m high building throws a ball with a speed of 10 m/s at an angle of ${30}^{\circ }$ with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground $(g=10m/s^2,sin{30}^{\circ }=\frac{1}{2},cos{30}^{\circ }=\frac{\sqrt{3}}{2})$

Q. A boy playing on the roof of a $10\text{m}$ high building throws a ball with a speed of $10\text{m/s}$ at an angle of ${30}^o$ with the horizontal. How far from the throwing point will the ball be at the height of $10\text{m}$ from the ground?
$[g=10{\text{m/s}}^2,\sin {30}^0=\frac{1}{2},\cos {30}^0=\frac{\sqrt{3}}{2}]$

Q. A boy playing on the roof of a $10m$ high building throws a ball with a speed of $10m/s$ at an angle of ${30}^{\circ }$ with the horizontal. The time taken by the ball to cross the point which is at the height of $10m$ from the ground is

Q. A boy standing on a long railroad car throws a ball straight upwards with a speed of $10\text{m/s}$ at $t=0$ when the car starts moving on a horizontal road with an acceleration of $1{\text{m/s}}^2$. How far behind the boy will the ball fall on the car? (Take $g=10{\text{m/s}}^2$).