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Question

A boy projects a stone vertically perpendicular to the trolley car with a speed v. If the trolley car moves with a constant velocity u, the time of flight of the stone is:

A
2vg
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B
u+v2g
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C
none of these
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D
2ug
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Solution

The correct option is C none of these
Resolve the velocity 𝑣 into horizontal and vertical component.

v0sinθ=v
v0cosθ=u

Time of flight depends on vertical component of velocity.

T=2v0sinθg=2vg

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