A boy projects a stone vertically perpendicular to the trolley car with a speed v. If the trolley car moves with a constant velocity u, the time of flight of the stone is:
A
2vg
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B
u+v2g
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C
none of these
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D
2ug
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Solution
The correct option is C none of these Resolve the velocity 𝑣 into horizontal and vertical component.
v0sinθ=v v0cosθ=u
Time of flight depends on vertical component of velocity.