A bullet is fired at an angle of $15^{\circ}$ with the horizontal and hits the ground 6 km away. Is it possible to hit a target 10 km away by adjusting the angle of projection assuming the initial speed will be the same.

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Solution

Range $R = u^{2} S i n 2 θ / g = 6000 m e t e r$
so $u^{2} = 120000 m / s$ so $u = 346.4 m / s$
Note, we used $S i n 2 θ = S i n 30^{0} = 0.5$
Now we know that the maximum value of range is given as $R_{m a x} = u^{2} / g = 120000 / 10 = 12000 m e t e r = 12 K m$
So its possible to hit the target at 10Km distance because its less than maximum range.

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A bullet is fired at an angle of 15∘ with the horizontal and hits the ground 6 km away. Is it possible to hit a target 10 km away by adjusting the angle of projection assuming the initial speed will be the same.

Range R=u2Sin2θ/g=6000meterso u2=120000m/s so u=346.4m/sNote, we used Sin2θ=Sin300=0.5Now we know that the maximum value of range is given as Rmax=u2/g=120000/10=12000meter=12KmSo its possible to hit the target at 10Km distance because its less than maximum range.

A bullet is fired at an angle of $15^{\circ}$ with the horizontal and hits the ground 6 km away. Is it possible to hit a target 10 km away by adjusting the angle of projection assuming the initial speed will be the same.