A bullet is fired from a canon with velocity 500 m/s. If the angle of projection is ${15}^{\circ }$ and $g=10m/s^2$. Then the range is

Q.

A bullet is fired from a cannon with velocity 500 m/s. If the angle of projection is ${15}^{\circ }$ and $g=10m/s^2$. Then the range is

Q.

A bullet is fired from a cannon with velocity 500 m/s. If the angle of projection is ${15}^{\circ }$ and $g=10m/s^2$. Then the range is

Q. A bullet is fired from a cannon with velocity $500$ $m/s$. If the angle of projection is ${15}^o$ and $g=10$ $m{s}^{-2}$, then the range is :

Q. A cannon is to fire up to $500m$ horizontally. What should be the angle of projection, if the shells are fired with a velocity of $100m/s$? $(g=10m/s^2)$

Q. The horizontal range of a bullet fired with angle of projection ${45}^o$ to the horizontal is $360m$. If it is fired from a lorry moving in the direction of bullet with the uniform velocity $18km$ $h^{-1}$ and with same elevation, what is the new range horizontal distance traveled by the bullet (Take $g=10m{s}^{-2}$).