A car moves at a speed of 40km/h, It is stopped by applying brakes which produces a uniform acceleration of -0.6m/s². How much distance will the vehicle move before coming to stop? [3 Marks]

Given:
u = 40 km/h = 11.11 m/s ,
a = -0.6m/s²,
v=0

From 3rd equation of motion:
$v^2$ = $u^2$ + 2as [1 Mark]
0 = ${11.11}^2$ - 2 * 0.6 * s
s = 102.87 m [2 Marks]

Hence, the car will move a distance of 102.87 metres before coming to stop.