A car moving with uniform acceleration covers 450 m in a 5 second interval, and covers 700 m in the next 5 seconds interval. The acceleration of the car is

The correct option is D $10m/s^2$
When car covers 450 m

$S=ut+\frac{1}{2}a{t}^2$

$450=5u+\frac{1}{2}\times a\times (5{)}^2....(1)$

When car covers remaining 700 m also

$1150=10u+\frac{1}{2}\times a\times (10{)}^2....(2)$

Solving equation (1) and (2)

$u=65m/sec$

$a=10m/se{c}^2$