A car travel first 13rd of the total distance at 30-km-hr- next 13rd of the total distance at 40-km-hr and last 13rd of the total distance at 24-km-hr- It-s average speed in km-hr for the whole Journey is30284035

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Finding Average Velocity

A car travel ...

Question

A car travel first $\frac{1}{3} r d$ of the total distance at $30 km/hr$ , next $\frac{1}{3} r d$ of the total distance at $40 km/hr$ and last $\frac{1}{3} r d$ of the total distance at $24 km/hr$ . It's average speed in $km/hr$ for the whole Journey is

40

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35

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30

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28

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Solution

The correct option is C $30$
The whole journey is shown in the below figure.

We know that average speed is given as
$v_{a v g} = \frac{Total distance}{Total time}$
$v_{a v g} = \frac{S}{t_{1} + t_{2} + t_{3}}$
$v_{a v g} = \frac{S}{\frac{S}{3 (30)} + \frac{S}{3 (40)} + \frac{S}{3 (24)}}$
$\Rightarrow v_{a v g} = \frac{360}{12} = 30 km/hr$

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A car travel first 13rd of the total distance at 30 km/hr, next 13rd of the total distance at 40 km/hr and last 13rd of the total distance at 24 km/hr. It's average speed in km/hr for the whole Journey is

The correct option is C 30The whole journey is shown in the below figure. We know that average speed is given as vavg=Total distanceTotal time vavg=St1+t2+t3 vavg=SS3(30)+S3(40)+S3(24) ⇒ vavg=36012=30 km/hr

A car travel first $\frac{1}{3} r d$ of the total distance at $30 km/hr$ , next $\frac{1}{3} r d$ of the total distance at $40 km/hr$ and last $\frac{1}{3} r d$ of the total distance at $24 km/hr$ . It's average speed in $km/hr$ for the whole Journey is