A car travels a distance of $200 km$ along a straight road at a speed of $40 km/h$ . The car returns back to same location with a speed of $60 km/h$ . Find the average speed and the average velocity of the car for the entire journey.

Average speed

= 48 km/h,

Average velocity

= 0 km/h

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Average speed

= 24 km/h,

Average velocity

= 12 km/h

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Average speed

= 48 km/h,

Average velocity

= 48 km/h

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Average speed

= 24 km/h,

Average velocity

= 24 km/h

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Solution

The correct option is A Average speed $= 48 km/h,$ Average velocity $= 0 km/h$

Average speed $= \frac{Total distance travelled}{Total time}$
$= \frac{400 km}{\frac{200 km}{40 km/h} + \frac{200 km}{60 km/h}} = \frac{400}{\frac{200}{10} (\frac{1}{4} + \frac{1}{6})} km/h$
$= \frac{20 \times 24 km}{(6 + 4) h} = 48 km/h$
Average velocity $= \frac{Displacement}{Time taken} = 0$
Because displacement is zero.
Alternate method:
$V_{av} = \frac{2 V_{1} V_{2}}{V_{1} + V_{2}} = \frac{2 \times 40 \times 60}{100} = 48 km/h$

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A car travels a distance of 200 km along a straight road at a speed of 40 km/h. The car returns back to same location with a speed of 60 km/h. Find the average speed and the average velocity of the car for the entire journey.

A car travels a distance of $200 km$ along a straight road at a speed of $40 km/h$ . The car returns back to same location with a speed of $60 km/h$ . Find the average speed and the average velocity of the car for the entire journey.