A cart of mass $50\text{kg}$ is moving on a straight track with a speed of $12\text{m/s}$. A mass of $10\text{kg}$ is gently put into the cart. What will be the velocity of the cart after this?

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Where is collision happening in this question? How to solve it?A cart of mass 50 kg is moving on a straight track with a speed of 12 metre per second a mass of 10 kg is gently put into the card what will be the velocity of the cart after this

Q. A cart of total mass $50\text{kg}$ is at rest on a horizontal road having coefficient of friction 0.1. Gases are ejected from this cart backwards with velocity $20\text{m/s}$ w.r.t the cart. The rate of ejection of gases is $2\text{kg/s}$. The cart will start moving after time $t=$ (seconds) [Take $g=10{\text{m/s}}^2$]

Q. You are standing on a cart moving at constant speed of 20 $m{s}^{-1}$ towards the left of a frictionless track. Suppose the mass of the cart along with your mass is 100 kg. There are 4 balls each of mass 2 kg in the cart that is now moving at a constant speed. If you throw a ball straight up with a velocity 20 $m{s}^{-1}$, how will the speed of the cart change?

Q. A cart loaded with sand having total mass $900\text{kg}$ moves on a straight horizontal road under the action of a force $60\text{N}$. If cart is starting from rest and sand spills through a small hole at the bottom of cart at a rate of $0.25\text{kg/s},$ what will be the speed of cart after $10$ $\text{minutes}$?
Given: $g=10{\text{m/s}}^2,\ln \left(\frac{5}{6}\right)\approx -0.2$

Q. A cart loaded with sand having total mass $900\text{kg}$ moves on a straight horizontal road under the action of a force $60\text{N}$. If cart is starting from rest and sand spills through a small hole at the bottom of cart at a rate of $0.25\text{kg/s},$ what will be the speed of cart after $10$ $\text{minutes}$?
Given: $g=10{\text{m/s}}^2,\ln \left(\frac{5}{6}\right)\approx -0.2$