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Question

A charged particle, having charge q accelerated through a potential difference V enters a perpendicular magnetic field in which it experiences a force F. If V is increased to 5V,the particle will experience a force

A
F
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B
5F
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C
0.2F
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D
5F
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Solution

The correct option is C 5F
12mv2=qV
So v=2qVm
F1=qvB=q2qVmB
F2=q2q×5VmB
F2=5F1

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