A charged particle with charge $q$ is moving in a uniform magnetic field. If this particle makes any angle with the magnetic field then its path will be :

The correct option is C helical
The component of velocity( $v_{\parallel }$) parallel to magnetic field $\overrightarrow{B}$ will make the charged particle move parallel or anti parallel to $\overrightarrow{B}$
The $v_{\perp }$ will make the particle move in a circle, plane of the circle being perpendicular to the direction of the magnetic field.