A coin is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 $m / s^{2}$ , with what velocity and after what time will it strike the ground?

20m/s, 2s

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10m/s, 1 s

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30m/s, 2s

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20m/s, 5s

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Solution

The correct option is A
20m/s, 2s

Here,

u = 0 , s = 20m , a =10 $m / s^{2}$

$v^{2}$ = $u^{2}$ + 2as

$v^{2}$ = 0 + (2 x 10 x 20)

$v^{2}$ = 400

v = 20 m/s

Hence the velocity with which it strikes teh ground is 20 m/s.

Also,

v = u + at

20 = 0 + 10t

t = 2s

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A coin is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10m/s2, with what velocity and after what time will it strike the ground?

The correct option is A 20m/s, 2s Here, u = 0 , s = 20m , a =10m/s2 v2 = u2 + 2as v2= 0 + (2 x 10 x 20) v2 = 400 v = 20 m/s Hence the velocity with which it strikes teh ground is 20 m/s. Also, v = u + at 20 = 0 + 10t t = 2s

A coin is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 $m / s^{2}$ , with what velocity and after what time will it strike the ground?

The correct option is A
20m/s, 2s

Here,

u = 0 , s = 20m , a =10 $m / s^{2}$

$v^{2}$ = $u^{2}$ + 2as

$v^{2}$ = 0 + (2 x 10 x 20)

$v^{2}$ = 400

v = 20 m/s

Hence the velocity with which it strikes teh ground is 20 m/s.

Also,

v = u + at

20 = 0 + 10t

t = 2s