A colour blind male $(X^{c} Y)$ marries a carrier female $(X^{C} X^{c})$ . Possible genotype of daughters will be _______________.

X^{c} X^{c}

only

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X^{C} X^{C}

only

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X^{C} X^{C}

and

X^{c} X^{c}

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X^{C} X^{c}

and

X^{c} X^{c}

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Solution

The correct option is D $X^{C} X^{c}$ and $X^{c} X^{c}$
Color blindness is X-linked recessive. The daughter will get one X chromosome from her father and one X chromosome from her mother. Father will contribute the affected X chromosome whereas mother can the affected X chromosome or she can pass the normal X chromosome.

So, the correct answer is ' $X^{C} X^{c}$ and $X^{c} X^{c}$ '.

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Similar questions

Q. A couple with four children have two boys (i) Normal boy (ii) Colour-blind boy and none of two daughters is colorblind. Find out the correct genotype of parents.

	Mother	Father
(A)	$X^{C} X^{c}$	$X^{c} Y$
(B)	$X^{c} X^{c}$	$X^{c} Y$
(C)	$X^{C} X^{C}$	$X^{C} Y$
(D)	$X^{C} X^{c}$	$X^{C} Y$

Q. A colour blind man

(X^{C} Y)

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(X^{C} X^{C})

and a normal brother (XY). What is genotype of father and mother.

Q. Colour blindness is a X linked recessive disorder in which the eye fails to distinguish between red and green colours. If a colour blind woman with genotype (

X^{C} X^{C}

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A normal male marries a female who is a carrier of colour blindness. What is the possibility of this couple having a son suffering from colour blindness?

Q. A normal vision female whose father is colour-blind marries a normal vision male. What would be the probability of her sons and daughters to be color blind?

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A colour blind male (XcY) marries a carrier female (XCXc). Possible genotype of daughters will be _______________.

A colour blind male $(X^{c} Y)$ marries a carrier female $(X^{C} X^{c})$ . Possible genotype of daughters will be _______________.