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A compound AB crystallizes in bcc lattice with unit cell edge length of 480 pm. If radius of B- is 225 pm then radius of A+ is
A compound AB crystallizes in bcc lattice with unit cell edge length of 480 pm. If radius of B- is 225 pm then radius of A+ is
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Solution
ANSWER...
In BCC lattice
Sphere or atoms are present in Body Centre and at each corner..
We know body diagonal distance (√3a=480×√3)
Now by this..
―»2(Anion + Cation)= 480√3
―»2(225+x)=480√3
―»450+2x=480√3
―»2x=480×1.73-450
―» x=(830.4 - 450)/2
―» X=190.2 pm
In BCC lattice
Sphere or atoms are present in Body Centre and at each corner..
We know body diagonal distance (√3a=480×√3)
Now by this..
―»2(Anion + Cation)= 480√3
―»2(225+x)=480√3
―»450+2x=480√3
―»2x=480×1.73-450
―» x=(830.4 - 450)/2
―» X=190.2 pm
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