A compound $M_{p} X_{q}$ has cubic close packing (ccp) arrangement of X. Its unit cell structure is shown below. The empirical formula of the compound is

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M X_{2}

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M_{2} X

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M_{5} X_{14}

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Solution

The correct option is B $M X_{2}$
Number of M atoms = $\frac{1}{4} \times 4 + 1 = 1 + 1 = 2$
Number of X atoms = $\frac{1}{2} \times 6 + \frac{1}{8} \times 8 = 3 + 1 = 4$
So, formula of compound is $M_{2} X_{4} = M X_{2}$

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