A compound microscope consists of an objective lens with focal length 1.0 cm and eye piece of focal length 2.0cm and a tube length 20cm the magnification is

Q. A microscope consists of an objective with a focal length 2 mm and an eye piece with a focal length 40mm. The distance between the foci (which are between the lenses) of objective and eyepiece is 18 cm. The total magnification of the microscope is (Consider normal adjustment and take D $=$ 25 cm)

Q. A compound microscope has an objective lens of $1.0cm$ focal length and an eye-piece of $2.5cm$ of focal length. When the object is placed at $1.1cm$ from the objective, the final image is at the least distance of direct vision. Thus, the magnification produced is

Q. A compound microscope consists of an objective lens of focal length $1\text{cm}$ and an eye piece of focal length $5\text{cm}$ with a separation of $10\text{cm}$. The distance between an object and the objective lens, at which the strain on the eye is minimum is $\frac{n}{40}\text{cm}$. The value of $n$ is

Q. A compound microscope consists of an objective lens of focal length $2$ cm and eye-piece of focal length $6.25$ cm separated by a distance of $15$ cm.length $6.25$ cm separated by a distance Find the object distance of the image:

Q. The tube length of microscope is 10 cm and the focal length of its objective is 5 cm. If the eye lens has focal length 0.5 cm. then the magnification of microscope for relaxed eye is :