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Lens Maker's Formula

A compound mi...

Question

A compound microscope has a magnification 30. The focal length of eyepiece is 5 cm. Assuming that the final image is formed at least distance of distinct vision (25 cm). Find the magnification produced by objective.

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Solution

Given,

Magnification, $M = 30$

Focal length, $f = 5 c m$

Final distance, $D = 25 c m$

In a compound microscope, $M = m_{o} \times m_{e}$

Thus,

30 = $m_{o} (1 + \frac{D}{f})$

30 = $m_{o} (1 + \frac{25}{5})$

Thus, $m_{o} = 5$

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