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Question

A compound microscope has a magnifying power 48. The focal length of its eye-piece is 5cm. If final image is formed at least distance of distinct vision (25cm) then magnification of objective lens is

A
8
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B
8
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C
200
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D
200
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Solution

The correct option is A 8
M=48
tc=5cm,D=25cm
Now, M=M0×Me=M0×[1+Dfe]
48=M0×[1+255]
48=M0[6]
M0=8

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