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Question

A compound microscope has an objective of focal length 4mm and an eyepiece of focal length 25 mm. The objective produces a real image at a distance of 180 mm. If the eye-piece is in normal adjustment, then the magnification is

A
45
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B
90
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C
225
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D
440
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Solution

The correct option is D 440
f0=4mm

fe=25mm

v0=180mm

MD=?

MD=v0v0[1+Dfe]

1v01v0=1f0

11801v0=14

1v0=1145

MD=180×1145[10]=180×1145×10 =440

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