Question 52
A compounds C (molecular formula $C_{2} H_{4} O_{2}$ ) reacts with $Na$ metal to form a compound R and evolves a gas which burns with a pop sound. Compound C on treatment with an alcohol A in presence of acid forms a sweet smelling compound S (molecular compounds $C_{3} H_{6} O_{2}$ ). On addition of $NaOH$ to C, it also gives R and water. S on treatment with $NaOH$ solution gives back R and A. Identify C, R, A, S and write down the reactions involved.

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Solution

C- Ethanoic acid
R- Sodium salt of Ethanoic acid and gas evolved is Hydrogen
A- Methanol
S- Ester

(a) $2 C H_{3} C O O H + 2 N a \to 2 C H_{3} C O O N a + H_{2} O$
(b) $C H_{3} C O O H + C H_{3} O H C H 3 C O O C H_{3} + H_{2} O$
(c) $C H_{3} C O O H + N a O H \to C H_{3} C O O N a + H_{2} O$
(d) $C H_{3} C O O C H_{3} + N a O H \to C H_{3} C O O N a + C H_{3} O H$

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Q. An organic compound A (molecular formula C₂H₄O₂) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C₃H₆O₂). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D.

An organic compound A (molecular formula $C_{2} H_{4} O_{2})$ reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula $C_{2} H_{6} O_{2})$ . Compound D on treatment with NaOH solution gives back B and C. Indentity A, B, C and D.