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Lens Formula and Magnification

A concave len...

Question

A concave lens has a focal length of 15cm. At what distance should the object from the lens be placed so that it forms an erect and virtual image at 10cm from the lens?

A

30cm

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B

15cm

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C

60cm

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D

10cm

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E

30cm

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F

15cm

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G

60cm

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H

10cm

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Solution

The correct option is A 30cm
From lens formula we have,

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f} \frac{1}{u} = \frac{1}{v} - \frac{1}{f} \frac{1}{u} = (\frac{- 1}{10}) - (\frac{- 1}{15}) \frac{1}{u} = \frac{- 1}{30} \Rightarrow u = - 30 c m$

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