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Question

A container shown in figure contains a liquid to a depth H, and of density ρ. The gauge pressure at point P is

A
ρgH2+P0
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B
ρgH2
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C
ρgH2cosθ
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D
ρgHcosθ2
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Solution

The correct option is B ρgH2
Formula used: Pgauge=PtotalPatm,P=ρgh
Given :h=H2
From the diagram we can see that depth of point P is H2
Gauge pressure will be equal to Pgauge=(Patm+ρgh)Patm=ρgh
h=H2
Gauge pressure is Hρg2

FINAL ANSWER: (b)


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