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Byju's Answer
Standard IX
Physics
Second Law of Motion
A cricket bal...
Question
A cricket ball of mass
100
g
moving with a velocity of
30
m
/
s
is brought to rest by a player in
0.03
s
e
c
find Rate of change in momentum of ball
.
A
10
N
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B
20
N
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C
100
N
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D
None of these
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Solution
The correct option is
C
100
N
I guess the question is the rate of change in momentum
Mass
=
0.1
k
g
Initial Momentum
=
m
×
s
p
e
e
d
(
u
)
=
0.1
×
30
=
3
Final Momentum=
m
×
r
e
s
t
(
v
)
=
0.1
×
0
=
0
Change in Momentum= Final-Initial
=
0
−
3
=
−
3
Rate of change in momentum
=
(
change in momentum
)
÷
time taken
=
(
−
3
)
÷
0.03
=
−
100
Hence,
option
(
C
)
is correct answer.
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