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Question

A cricket ball of mass 100g moving with a velocity of 30m/s is brought to rest by a player in 0.03 sec find Rate of change in momentum of ball.

A
10N
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B
20N
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C
100N
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D
None of these
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Solution

The correct option is C 100N
I guess the question is the rate of change in momentum
Mass=0.1kg
Initial Momentum=m×speed (u)=0.1×30=3
Final Momentum= m×rest (v)=0.1×0=0
Change in Momentum= Final-Initial =03=3
Rate of change in momentum=(change in momentum)÷time taken
=(3)÷0.03
=100
Hence,
option (C) is correct answer.

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