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Byju's Answer
Standard XII
Chemistry
Units and Dimensions
A cricket bal...
Question
A cricket ball of mass
200
g
m
moving with velocity
15
m
/
s
is brought to rest by a player in
0.05
s
e
c
. What is the impulse of the ball and average force exerted by player?
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Solution
I
m
p
u
l
s
e
=
c
h
a
n
g
e
i
n
m
o
m
e
n
t
u
m
=
m
(
v
−
u
)
=
0.2
(
0
−
15
)
=
−
3
N
s
A
v
e
r
a
g
e
f
o
r
c
e
=
I
m
p
u
l
s
e
/
T
i
m
e
=
3
0.05
=
60
N
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Q.
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