wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cricket ball of mass 200 gm moving with velocity 15 m/s is brought to rest by a player in 0.05 sec. What is the impulse of the ball and average force exerted by player?

Open in App
Solution

Impulse=change in momentum=m(vu)=0.2 (015)=3Ns
Average force=Impulse/Time=30.05=60 N

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Measurement of Significant Figures
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon