wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cricketer hits a ball with a velocity 25 m/s at 60 above the horizontal. How far above the ground it passes over a fielder 50m from the bat (assume the ball is struck very close to the ground)

A
8.2 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
9.0 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
11.6 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12.7 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 8.2 m

Horizontal component of velocity
vx = 25 cos 60 = 12.5 m/s
Vertical component of velocity
vy = 25 cos 60 = 12.5 3 m/s
Time to cover 50 m distance t = 5012.5 = 4 sec

The vertical height y is given by
y = vyt - 12gt2 = 12.5 3×412×9.8×16 = 8.2m


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving n Dimensional Problems
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon