A cylinder containing cooking gas can withstand a pressure of 15 atm- The pressure gauge of the cylinder indicates 12 atm at 27- C-Due to a sudden fire in the building- the temperature starts rising- At what temperature will the cylinder explode- -

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Standard XII

Chemistry

Ideal Gas Equation

A cylinder co...

Question

A cylinder containing cooking gas can withstand a pressure of 15 atm. The pressure gauge of the cylinder indicates 12 atm at $27^{\circ} C$ . Due to a sudden fire in the building, the temperature starts rising. At what temperature will the cylinder explode?

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Solution

The correct option is C

Given, $P_{1}$ = 15 atm, $T_{1}$ = ?

$P_{2}$ = 12 atm, $T_{2}$ = 300 K (273+27)

Since the volume of the cylinder remains constant,
$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

Therefore, $\frac{15}{T_{1}} = \frac{12}{300}$

$T_{1}$ = 375 K.

i.e., the cylinder will explode above 375 K or $102^{\circ} C$ .

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