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Question

A cylinder containing water up to a height of 24 cm has a hole in its bottom. It is counter-poised in a balance. When water begins to flow out, the initial decrease in balancing weight is required to be 12 gf to keep the balance beam horizontal. The cross-sectional area of the hole is :
25030_ea4d9a39f2144e5488daf94692bebb0c.png

A
0.12 cm2
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B
0.25 cm2
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C
0.50 cm2
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D
0.75 cm2
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Solution

The correct option is A 0.25 cm2
From Toricellis theorem v=2gh
So, force exerted by the let of liquid on cylinder =fav2 ...........(1) [where a is cross sectional area]
Decrease in balancing weight =2gh.............(2)
So, in order to balance,
(1)=(2)
λa,2g×24=12×ga=122×24cm2a=0.25cm2

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