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Question

A. ΔG is net energy available to do useful work and is thus a measure of "free energy". Show mathematically that ΔG is a measure of free energy.

B. Find the unit of ΔG. If a reaction has positive enthalpy change and positive entropy change, under what condition will the reaction be spontaneous?

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Solution

  • We know that,

ΔSTotal=ΔSsys+ΔSsurr
  • If the system is in thermal equilibrium with the surrounding, then the temperature of the surrounding is same as that of the system.

Also, increase in enthalpy of the surrounding is equal to decrease in the enthalpy of the system.

Therefore, entropy change of surroundings,

ΔSsurr=ΔHsurrT=ΔHsysT

ΔSTotal=ΔSsys+ΔHsysT

TΔSTotal=TΔSsysΔHsys

For spontaneous change, ΔSTotal>0

TΔSTotalΔHsys>0

=>(ΔHsysTΔSsys)>0

But, ΔHsysTΔSsys=ΔGsys

ΔGsys>0

=>ΔGsys=ΔHsysTΔSsys<0
  • ΔHsys is the enthalpy change of a reaction, TΔSsys is the energy which is not available to do useful work.
  • So ΔGsys is the net energy available to do useful work and is thus a measure of the ‘free energy’. For this reason, it is also known as the free energy of the reaction.
  • ΔG has the unit of energy because both ΔH and TΔSsys are terms of energy.

The unit of free energy change is same as the unit of energy i.e., joule (J).

If a reaction has positive enthalpy change and positive entropy change then the reaction will be spontaneous at high temperatures.

ΔGsys=ΔHsysTΔSsys

For positive values of enthalpy change and entropy change, large values of temperature will make ΔGsys<0.

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