a dishonest milkman has one bucket of milk of 80% purity. he has another bucket of milk of 50% purity. how much milk of each kind should he mix to supply 20 litres of milk of 70% purity

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$Let x litres of 80 % purity milk should be added to 50 % purity milk . Now, x + y = 20 . . . . . (1) Also, 80 % of x + 50 % of y = 70 % of 20 \Rightarrow 8 x + 5 y = 140 . . . . . . (2) Multiply (1) by 5, we get 5 x + 5 y = 100 . . . . . (3) Subtract (3) from (2), we get 3 x = 40 \Rightarrow x = \frac{40}{3} litres Now, from (1), we get y = \frac{20}{3} litres$

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a dishonest milkman has one bucket of milk of 80% purity. he has another bucket of milk of 50% purity. how much milk of each kind should he mix to supply 20 litres of milk of 70% purity

Let x litres of 80% purity milk should be added to 50% purity milk.Now, x + y = 20 .....1Also, 80% of x + 50% of y = 70% of 20⇒8x + 5y = 140 ......2Multiply 1 by 5, we get5x + 5y = 100 .....3Subtract 3 from 2, we get3x = 40⇒x = 403 litresNow, from 1, we gety = 203 litres