A farmer moves along the boundary of a square field of slide 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?

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Solution

Figure ABCD is squire field side of $10 m .$
Time for one round= $40$
Total time= $2 m 20 s e c$
$(2 \times 60 + 20 = 140 s)$
Number of round completed
If farmer start from A ,it will complete 3 rounds A
At A .In the last $0.5 r o u n d s$
starting from A .
He will finish at C.

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A farmer moves along the boundary of a square field of slide 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?

Figure ABCD is squire field side of 10m.Time for one round=40Total time=2m20sec(2×60+20=140s)Number of round completed If farmer start from A ,it will complete 3 rounds AAt A .In the last 0.5rounds starting from A .He will finish at C.

Figure ABCD is squire field side of $10 m .$
Time for one round= $40$
Total time= $2 m 20 s e c$
$(2 \times 60 + 20 = 140 s)$
Number of round completed
If farmer start from A ,it will complete 3 rounds A
At A .In the last $0.5 r o u n d s$
starting from A .
He will finish at C.