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Standard IX

Physics

Second Law of Motion

A force of 25...

Question

A force of 25 newton is applied on an object of mass 10 kg moving with a velocity of 5 m s $^{- 1}$ . If the object gains a velocity of 10 m s $^{- 1}$ . Calculate the time interval.

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Solution

acceleration, a = $\frac{F}{m}$ = $\frac{25}{10}$ =2.5m/s $^{2}$
Using v = u + at
we get, v - u = at (velocity gain is 10m/s, so v-u = 10)
10 = 2.5t
t = 4s

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A force of 25 newton is applied on an object of mass 10 kg moving with a velocity of 5 m s $^{- 1}$ . If the object gains a velocity of 10 m s $^{- 1}$ . Calculate the time interval.

acceleration, a = $\frac{F}{m}$ = $\frac{25}{10}$ =2.5m/s $^{2}$
Using v = u + at
we get, v - u = at (velocity gain is 10m/s, so v-u = 10)
10 = 2.5t
t = 4s

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A force of 25 newton is applied on an object of mass 10 kg moving with a velocity of 5 m s−1. If the object gains a velocity of 10 m s−1. Calculate the time interval.

acceleration, a = Fm=2510=2.5m/s2Using v = u + atwe get, v - u = at (velocity gain is 10m/s, so v-u = 10) 10 = 2.5t t = 4s

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FREE TEXTBOOK SOLUTIONS

STATE BOARDS

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A force of 25 newton is applied on an object of mass 10 kg moving with a velocity of 5 m s $^{- 1}$ . If the object gains a velocity of 10 m s $^{- 1}$ . Calculate the time interval.

acceleration, a = $\frac{F}{m}$ = $\frac{25}{10}$ =2.5m/s $^{2}$
Using v = u + at
we get, v - u = at (velocity gain is 10m/s, so v-u = 10)
10 = 2.5t
t = 4s