A fruit is dropped from a height of 20 m. Find the velocity with which it would hit the ground. Take g = $10 m s^{- 2}$

40 m/s

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50 m/s

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20 m/s

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Solution

The correct option is C
20 m/s

Since, the acceleration is along the direction of motion, a = + $10 m s^{- 2}$ , initial velocity u= 0 and height s= 20 m.
Using $v^{2}$ = $u^{2}$ + 2as
$v^{2}$ = 0 + 2 $\times$ 10 $\times$ 20 = 400
v = $\sqrt{400}$ = 20 $m s^{- 1}$

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A fruit is dropped from a height of 20 m. Find the velocity with which it would hit the ground. Take g = 10 ms−2

The correct option is C 20 m/s Since, the acceleration is along the direction of motion, a = + 10ms−2, initial velocity u= 0 and height s= 20 m. Using v2​ = u2​​ + 2as v2​ =​ 0 + 2 × 10 × 20​ = 400 v = √400 = 20 ms−1

A fruit is dropped from a height of 20 m. Find the velocity with which it would hit the ground. Take g = $10 m s^{- 2}$

The correct option is C
20 m/s

Since, the acceleration is along the direction of motion, a = + $10 m s^{- 2}$ , initial velocity u= 0 and height s= 20 m.
Using $v^{2}$ = $u^{2}$ + 2as
$v^{2}$ = 0 + 2 $\times$ 10 $\times$ 20 = 400
v = $\sqrt{400}$ = 20 $m s^{- 1}$