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Question

A galvanic cell is constructed by coupling a copper and a zinc electrode. If at 298 K:
ECu2+(aq)/Cu(s)=+0.34 V
EZn2+(aq)/Zn(s)=0.76 V

Which of the following is/are correct?

A
Zn2+ has a higher oxidising power.
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B
Cu2+ has a higher oxidising power.
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C
EZn(s)/Zn2+(aq)=+0.76 V
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D
ECu(s)/Cu2+(aq)=+0.34 V
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Solution

The correct option is C EZn(s)/Zn2+(aq)=+0.76 V
Higher the reduction potential, greater is the oxidising power and vice versa.
Standard reduction potentials of zinc and copper are given.
Since,
ECu2+(aq)/Cu(s)>EZn2+(aq)/Zn(s)
Cu2+ has a higher oxidising power and it gets reduced.

Reduction and oxidation potential for an electrode are equal in value and opposite in sign.
Oxidation potential=Reduction potential
At standard conditions:
Standard Oxidation potential=Standard Reduction potential
According to IUPAC convention, standard electrode potential is now expressed in terms of standard reduction potential

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