A gas has a vapour density 11.2.The volume occupied by 1 g of gas at NTP is :

The correct option is A 1 litre

Given :- vapour density = 11.2 weight of gas = 1 g

Molecular mass of gas = $2\times$ vapour density

$=2\times 11.2=22.4$

no. of moles of gas = $\frac{weight}{molecularmass}=\frac{1}{22.4}=0.045$

volume of gas = no. of moles $\times$ vapour density

$=0.045\times 22.4=1L$

Therefore, the option is A.