A jet airplane traveling at a speed of $500 k m / h$ ejects its products of combustion at the speed of $1500 k m / h$ relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?

- 1000 k m / h

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1000 k m / h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100 k m / h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 100 k m / h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $- 1000 k m / h$
Given,
Speed of jet with respect to latter, $v_{j l} = 500 k m / h$
Speed of latter with respect to jet, $v_{l j} = - 1500 k m / h$
Speed of the latter with respect to the ground is,
$v_{l g} = v_{j l} + v_{l j}$
$v_{l g} = 500 + (- 1500)$
$v_{l g} = - 1000 k m / h$
The correct option is A.

Suggest Corrections

Similar questions

500 km/h

1500 km/h

500 {km h}^{- 1}

1500 {km h}^{- 1}

500 k m h^{- 1}

1500 k m h^{- 1}

Join BYJU'S Learning Program