A jogger running at $9$ kmph alongside a railway track, $240$ metres ahead of the engine of a $120$ metres long train running at $45$ kmph in the same direction. In how much time will the train pass the jogger?

3.6

sec

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36

sec

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18

sec

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72

sec

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Solution

The correct option is B $36$ sec
Speed of train relative to jogger $= (45 - 9) k m / h = 36 k m / h$
$= 36 \cdot \frac{5}{18} m / s e c = 10 m / s e c$

Distance to be covered $= (240 + 120) m = 360 m$
$∴$ Time taken $= \frac{360}{10} = 36 s e c$

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A jogger running at 9 kmph alongside a railway track, 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

The correct option is B 36 secSpeed of train relative to jogger =(45−9) km/h=36 km/h =36⋅518 m/sec=10 m/sec Distance to be covered =(240+120) m=360 m ∴ Time taken =36010=36 sec

A jogger running at $9$ kmph alongside a railway track, $240$ metres ahead of the engine of a $120$ metres long train running at $45$ kmph in the same direction. In how much time will the train pass the jogger?

The correct option is B $36$ sec
Speed of train relative to jogger $= (45 - 9) k m / h = 36 k m / h$
$= 36 \cdot \frac{5}{18} m / s e c = 10 m / s e c$

Distance to be covered $= (240 + 120) m = 360 m$
$∴$ Time taken $= \frac{360}{10} = 36 s e c$