A linera hramonic oscillator of force costant 2×106N/m and amplitude 0.01m has a total mechanical energy 160J. Among the following statements, which are correct?
1
Maximum PE is 100J
2
Maximum KE is 100J
3
Maximum KE is 160
4
Manimum KE is Zero
A
Both (ii) and (iv)
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B
Both (i) and (ii)
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C
Both (ii) and (iii)
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D
Both (i) and (iv)
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Solution
The correct option is C Both (ii) and (iii) Given,
Total mechanical energy, ET=160J
Force constant, k=2×106N/m
Amplitude, A=0.001m
Maximum potential energy, ⇒Umax=160J
At extreme position, KE is zero.So, the work done by sprimg force from exreme position to mean position is, ⇒=2kA2
Maximum Kinetic energy of body, kmax=12(2×106)(0.012)kmax=(1×106)(1×10−4)kmax=100J
Maximum PE is 160J and maximum is KE is 100J
And minimum potential energy, Umin=160−100=60J