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Question

A man bails out from an aeroplane and after dropping vertically through a distance of 40 m, he opens parachute and decelerates at 2m/s2. If he reaches ground with speed of 2 𝑚/𝑠, how much distance did he travel in air?
(g=9.8 m/s2)

A
215 m
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B
235 m
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C
250 m
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D
195 m
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Solution

The correct option is B 235 m
After falling 40 𝑚,
he attains speed v2=02+2×9.8×40,
v=28 m/s

When parachutist decelerates uniformly,
u=28 m/s,v=2 m/s,a=2 ms2

Apply, v2=u2+2as,
22=282(2×2×s)
780=4 s
We get,s=195m

Height at which parachutist bailed out=195+40=235 m

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