wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man of 80 kg mass is standing on the rim of a circular platform of mass 100 kg rotating about its axis. The mass of the platform with the man on its rotates at 12 r.p.m. If the man moves to the center of the platform, the rotational speed (take platform as a circular ring)


A

21.6 rpm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

22.4rpm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

23.6 rpm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

24.2 rpm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

21.6 rpm


According to conservation of angular momentum,
Li=Lf
[(mMan)(R2)w]+[(mplatform)R2w]=(mplatform)R2w1
80R2w+100R2w=100R2w1
180R2w=100R2w1 w1=180×12100=21.6 rpm


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Momentum_tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon