A mass of 1 kg is acted upon by a single force $\overrightarrow{F}=(4\hat{i}+4\hat{j})N.$
Under this force it is displaced from (0, 0 ) to (1 m, 1 m). If initially the speed of the particle was 2 m/s, its final speed should be

Q. A particle of mass $2kg$ moves on a smooth horizontal plane under the action of a single force$\overrightarrow{F}=(3\hat{i}+\hat{j})N$. Under this force it is displaced from $(0,0)$ to $(1m,1m)$. The initial speed of the particle is $\surd 3m/s$ and final speed is $\surd 5km/s$. Find the value of $k$.

Q. A particle moves from a point (-1 m, 2 m) to (1 m, 2 m)due to a force acting on it. If the force is $\overrightarrow{F}=4\stackrel{\wedge }{i}N$, then work done by this force is :

Q. The figure shows the force (F) versus displacement (s) graph for a particle of mass $m=2kg$ initially at rest:
(a) The maximum speed of the particle occurs at $x=......m$.
(b) The maximum speed of the particle occurs is ........$m{s}^{-1}$.
(c) The particle once again has its speed zero at $x=...........m$.

Q. A particle of mass $2\text{kg}$ initially at origin $(0,0)$ moves with an initial velocity $\overrightarrow{V}=4\hat{i}+4\hat{j}\text{m/s}$. If a constant force $\overrightarrow{F}=-20\hat{j}\text{N}$ is applied on the particle, the $x-$coordinate of the particle when its $y-$coordinate again becomes zero is

Q. A body of mass $m={10}^{-2}kg$ is moving in a medium and experiences a frictional force$F=-k{v}^2$. Its initial speed is $v_0=10m/s$. If, after $10s$, its energy is $\frac{1}{8}m{v}_0^2$, the value of $k$ will be