A match box measures $4cm\times 2.5cm\times 1.5cm$.
The volume of a packet containing $12$ such boxes is:

The correct option is C $180c{m}^3$
Given:
Dimension of matchbox is $4cm\times 2.5cm\times 1.5cm$

Volume of the matchbox is given as the product of its dimensions.
$V=4\times 2.5\times 1.5$
$V=15c{m}^3$

The packet has 12 matchboxes. Hence, volume of packet is:
$V^{\prime }=12V$
$V^{\prime }=12\times 15c{m}^3$
$V^{\prime }=180c{m}^3$