A metal 'M' has shining appearance and reacts with hot water and also with dilute hydrochloric acid to evolve hydrogen gas. The metal 'M' is:

can be copper because it lies above hydrogen in the reactivity series, i.e., more reactive than hydrogen

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can be gold because it lies below hydrogen in the reactivity series, i.e., more reactive than hydrogen

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cannot be gold because it lies above hydrogen in the reactivity series, i.e., less reactivity than hydrogen

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cannot be copper because it lies below hydrogen in the reactivity series, i.e., less reactive than hydrogen

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Solution

The correct option is D cannot be copper because it lies below hydrogen in the reactivity series, i.e., less reactive than hydrogen
The reactivity series is a list of metals arranged in the order of their decreasing activities. The reactivity series follows the order:
$K > N a > C a > M g > A l > Z n > F e > P b > H > C u > H g > A g > A u$
Thus, 'M' can't be copper as it lies below hydrogen in the reactivity series.

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